What is (\partial)/(\partial x)(sqrt(3x-2y)) ?

The answer to (\partial)/(\partial x)(sqrt(3x-2y)) is 3/(2sqrt(3x-2y))

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(\partial)/(\partial x)(sqrt(3x-2y))

\frac{\partial}{\partial x} (3 x - 2 y)

\frac{3}{2 3 x - 2 y}

Solution steps

\frac{\partial}{\partial x} (3 x - 2 y)

Treat

y

as a constant

Apply the chain rule:

\frac{1}{2 3 x - 2 y} \frac{\partial}{\partial x} (3 x - 2 y)

= \frac{1}{2 3 x - 2 y} \frac{\partial}{\partial x} (3 x - 2 y)

\frac{\partial}{\partial x} (3 x - 2 y) = 3

= \frac{1}{2 3 x - 2 y} \cdot 3

Simplify

\frac{1}{2 3 x - 2 y} \cdot 3 : \frac{3}{2 3 x - 2 y}

= \frac{3}{2 3 x - 2 y}

x \to 0 - lim (b x + 8)

\frac{d}{d x} (2 + x e^{- 3 x})

\frac{\partial}{\partial x} (x^{\frac{1}{4}} \cdot y^{\frac{1}{2}})

(3 x^{2} + 3 x^{- 2} y) d x + (x^{2} y - x^{- 1}) d y = 0

\int_{0}^{2} π (x^{2} - L)^{2} d x

What is (\partial)/(\partial x)(sqrt(3x-2y)) ?
The answer to (\partial)/(\partial x)(sqrt(3x-2y)) is 3/(2sqrt(3x-2y))