What is the solution for 8(sin(t)y^'+cos(t)y)=cos(t)sin^5(t) ?

The solution for 8(sin(t)y^'+cos(t)y)=cos(t)sin^5(t) is y=(sin^5(t))/(48)+(c_{1})/(sin(t))

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8(sin(t)y^'+cos(t)y)=cos(t)sin^5(t)

8 (sin (t) y^{^{'}} + cos (t) y) = cos (t) sin^{5} (t)

y = \frac{sin ^{5} ( t )}{48} + \frac{c _{1}}{sin ( t )}

Solution steps

8 (sin (t) y^{'} (t) + cos (t) y) = cos (t) sin^{5} (t)

Solve linear ODE:

y = \frac{sin ^{5} ( t )}{48} + \frac{c _{1}}{sin ( t )}

y = \frac{sin ^{5} ( t )}{48} + \frac{c _{1}}{sin ( t )}

\frac{1}{1 + 5 x ^{2}}

f (x) = 5 x + 1, at x = 7

e^{- 3 x}

f (x) = x^{2} cot (x)

\int cos (ln (x)) d x

What is the solution for 8(sin(t)y^'+cos(t)y)=cos(t)sin^5(t) ?
The solution for 8(sin(t)y^'+cos(t)y)=cos(t)sin^5(t) is y=(sin^5(t))/(48)+(c_{1})/(sin(t))