What is the derivative of (x^3/6-3x) ?

The derivative of (x^3/6-3x) is (x^2)/2-3

What is the first derivative of (x^3/6-3x) ?

The first derivative of (x^3/6-3x) is (x^2)/2-3

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\frac{d}{d x} (\frac{x ^{3}}{6} - 3 x)

\frac{x ^{2}}{2} - 3

Solution steps

\frac{d}{d x} (\frac{x ^{3}}{6} - 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{3}}{6}) - \frac{d}{d x} (3 x)

\frac{d}{d x} (\frac{x ^{3}}{6}) = \frac{x ^{2}}{2}

\frac{d}{d x} (3 x) = 3

= \frac{x ^{2}}{2} - 3

\int \frac{1}{36} x d x

\int_{0}^{4} \frac{1}{x ^{2} - 2 x - 3} d x

\frac{d y}{d x} = \frac{2 x}{x ^{2} + 3} (y - 1)

\frac{1}{g ^{2} ( x )}

10 x (x^{2} + 5)^{4}

What is the derivative of (x^3/6-3x) ?
The derivative of (x^3/6-3x) is (x^2)/2-3
What is the first derivative of (x^3/6-3x) ?
The first derivative of (x^3/6-3x) is (x^2)/2-3