What is the sum from n=0 to infinity of sin((npi)/7) ?

The sum from n=0 to infinity of sin((npi)/7) is diverges

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sum from n=0 to infinity of sin((npi)/7)

n = 0 \sum \infty sin (\frac{nπ}{7})

diverges

Solution steps

n = 0 \sum \infty sin (\frac{nπ}{7})

Apply Series Divergence Test:

diverges

= diverges

\frac{d}{d x} (sinh (9 x))

\int_{0}^{1} (e^{x} + e^{- x})^{2} d x

\int 2 cos (2 x) - 2 d x

\frac{d}{d x} (\frac{x - 7}{x + 2})

\int \frac{1}{12 - 4 x - x ^{2}} d x

What is the sum from n=0 to infinity of sin((npi)/7) ?
The sum from n=0 to infinity of sin((npi)/7) is diverges