What is the limit as x approaches-1 of 1/(x^3-x) ?

The limit as x approaches-1 of 1/(x^3-x) is diverges

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limit as x approaches-1 of 1/(x^3-x)

x \to - 1 lim (\frac{1}{x ^{3} - x})

diverges

Solution steps

x \to - 1 lim (\frac{1}{x ^{3} - x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 1 + lim (\frac{1}{x ^{3} - x}) = \infty

x \to - 1 - lim (\frac{1}{x ^{3} - x}) = - \infty

= diverges

y^{8} - \frac{y ^{9} + 4}{x ^{3} 4 y ^{^{'}}} = 0

\int (- x x^{4}) d x

\int \frac{x ^{2}}{5 + x ^{3}} d x

\frac{\partial}{\partial t} (\frac{( s - 2 r )}{t})

y^{^{'}} + y + 4 sin (x) = 0

What is the limit as x approaches-1 of 1/(x^3-x) ?
The limit as x approaches-1 of 1/(x^3-x) is diverges