What is the derivative of (x^7/(x^4)) ?

The derivative of (x^7/(x^4)) is 3x^2

What is the first derivative of (x^7/(x^4)) ?

The first derivative of (x^7/(x^4)) is 3x^2

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\frac{d}{d x} (\frac{x ^{7}}{x ^{4}})

3 x^{2}

Solution steps

\frac{d}{d x} (\frac{x ^{7}}{x ^{4}})

Simplify

\frac{x ^{7}}{x ^{4}} : x^{3}

= \frac{d}{d x} (x^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 x^{3 - 1}

Simplify

= 3 x^{2}

x \to 0 lim (1 + \frac{1}{x ^{2}})

x^{3} - 2 x^{2} y - 2 y^{2} - 1

arcsin (\frac{x}{7})

y = 4^{- x} sin (x)

\int \frac{9 - x ^{2}}{7 x ^{3} + x} d x

What is the derivative of (x^7/(x^4)) ?
The derivative of (x^7/(x^4)) is 3x^2
What is the first derivative of (x^7/(x^4)) ?
The first derivative of (x^7/(x^4)) is 3x^2