What is the tangent of f(x)= 5/x ,\at x=1 ?

The tangent of f(x)= 5/x ,\at x=1 is y=-5x+10

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tangent of f(x)= 5/x ,\at x=1

tangent of

f (x) = \frac{5}{x}, at x = 1

y = - 5 x + 10

Solution steps

Find the tangent point:

(1, 5)

Find the slope of

f (x) = \frac{5}{x} : \frac{df ( x )}{d x} = - \frac{5}{x ^{2}}

Compute the slope of

f (x) = \frac{5}{x}

x = 1 : m = - 5

Find the line with slope m=

- 5

and passing through

(1, 5) : y = - 5 x + 10

y = - 5 x + 10

\int t e^{t} d t

\int \frac{x}{x ^{4} + 1} d x

y = \frac{1}{x ^{6}}, (1, 1)

\int \frac{4 x}{( 2 x ^{2} - 7 ) ^{10}} d x

3 t^{3}

What is the tangent of f(x)= 5/x ,\at x=1 ?
The tangent of f(x)= 5/x ,\at x=1 is y=-5x+10