What is the tangent of f(x)=3cot^4(x),\at x= pi/4 ?

The tangent of f(x)=3cot^4(x),\at x= pi/4 is y=-24x+3+6pi

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=3cot^4(x),\at x= pi/4

tangent of

f (x) = 3 cot^{4} (x), at x = \frac{π}{4}

y = - 24 x + 3 + 6 π

Solution steps

Find the tangent point:

(\frac{π}{4}, 3)

Find the slope of

f (x) = 3 cot^{4} (x) : \frac{df ( x )}{d x} = - 12 cot^{3} (x) csc^{2} (x)

Compute the slope of

f (x) = 3 cot^{4} (x)

x = \frac{π}{4} : m = - 24

Find the line with slope m=

- 24

and passing through

(\frac{π}{4}, 3) : y = - 24 x + 3 + 6 π

y = - 24 x + 3 + 6 π

\int \frac{3}{x ^{2} x ^{2} + 9} d x

\frac{d}{d x} (x^{e^{2}})

\int \frac{e ^{x}}{1 + 64 e ^{2 x}} d x

e^{3 x} \cdot ln (4 x)

x \to 2 lim (5 - 3 x)

What is the tangent of f(x)=3cot^4(x),\at x= pi/4 ?
The tangent of f(x)=3cot^4(x),\at x= pi/4 is y=-24x+3+6pi