What is the derivative of (x+y)^2 ?

The derivative of (x+y)^2 is 2(x+y)

What is the first derivative of (x+y)^2 ?

The first derivative of (x+y)^2 is 2(x+y)

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derivative of

(x + y)^{2}

2 (x + y)

Solution steps

\frac{d}{d x} ((x + y)^{2})

Treat

y

as a constant

Apply the chain rule:

2 (x + y) \frac{d}{d x} (x + y)

= 2 (x + y) \frac{d}{d x} (x + y)

\frac{d}{d x} (x + y) = 1

= 2 (x + y) \cdot 1

Simplify

= 2 (x + y)

x 2 - x^{2}

e^{- 3 t} sin (4 t)

\int \frac{1}{y ( y ^{2} + 1 )} d y

\int \frac{25 - 4 x ^{2}}{x} d x

What is the derivative of (x+y)^2 ?
The derivative of (x+y)^2 is 2(x+y)
What is the first derivative of (x+y)^2 ?
The first derivative of (x+y)^2 is 2(x+y)