What is (\partial)/(\partial x)(sin(xz^2)-xy^2) ?

The answer to (\partial)/(\partial x)(sin(xz^2)-xy^2) is cos(xz^2)z^2-y^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(sin(xz^2)-xy^2)

\frac{\partial}{\partial x} (sin (x z^{2}) - x y^{2})

cos (x z^{2}) z^{2} - y^{2}

Solution steps

\frac{\partial}{\partial x} (sin (x z^{2}) - x y^{2})

Treat

z, y

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (sin (x z^{2})) - \frac{\partial}{\partial x} (x y^{2})

\frac{\partial}{\partial x} (sin (x z^{2})) = cos (x z^{2}) z^{2}

\frac{\partial}{\partial x} (x y^{2}) = y^{2}

= cos (x z^{2}) z^{2} - y^{2}

\int x a e^{- a x} d x

y^{^{'}} + 3 t y = t, y (0) = 1

\int \frac{9}{x ( ln ( x ) ) ^{2}} d x

x \to 0 lim (x (cot (2 x)))

x, x^{2}

What is (\partial)/(\partial x)(sin(xz^2)-xy^2) ?
The answer to (\partial)/(\partial x)(sin(xz^2)-xy^2) is cos(xz^2)z^2-y^2