What is the solution for (1+cos(t))y^'=(1-e^{-y})sin(t) ?

The solution for (1+cos(t))y^'=(1-e^{-y})sin(t) is y=ln((c_{1})/(1+cos(t))+1)

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(1+cos(t))y^'=(1-e^{-y})sin(t)

(1 + cos (t)) y^{^{'}} = (1 - e^{- y}) sin (t)

y = ln (\frac{c _{1}}{1 + cos ( t )} + 1)

Solution steps

(1 + cos (t)) y^{'} (t) = (1 - e^{- y}) sin (t)

Solve separable ODE:

y = ln (\frac{c _{1}}{1 + cos ( t )} + 1)

y = ln (\frac{c _{1}}{1 + cos ( t )} + 1)

\int x^{2} (x^{3} - 4)^{3} d x

\frac{d}{d x} (\frac{6 x}{x ^{2} + 3})

\frac{d}{d x} (\frac{x - 7}{( x + 5 ) ^{10}})

x^{2} - 12 x + k

x \to 4 lim (x 25 - x^{2})

What is the solution for (1+cos(t))y^'=(1-e^{-y})sin(t) ?
The solution for (1+cos(t))y^'=(1-e^{-y})sin(t) is y=ln((c_{1})/(1+cos(t))+1)