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Popular >

area 2x-1, 1/x ,x=3

Solution

area

2 x - 1, \frac{1}{x}, x = 3

Solution

- ln (3) + 6

+1

Solution steps

Apply the area formula:

\int_{1}^{3} 2 x - 1 - \frac{1}{x} d x

Solve

\int_{1}^{3} 2 x - 1 - \frac{1}{x} d x : - ln (3) + 6

The area is:

= - ln (3) + 6

Popular Examples

(dy)/(dx)= 1/((2x+y+1))

\frac{d y}{d x} = \frac{1}{( 2 x + y + 1 )}

\frac{d y}{d t} = \frac{y}{t}

area y=(x^2-4x-4)/(x^2-4x-5),y=0 area

y = \frac{x ^{2} - 4 x - 4}{x ^{2} - 4 x - 5}, y = 0

6t((dy)/(dt))+y=t^3

6 t (\frac{d y}{d t}) + y = t^{3}

derivative of 4x^3+x+5sin(x)

\frac{d}{d x} (4 x^{3} + x + 5 sin (x))

Frequently Asked Questions (FAQ)

What is area 2x-1, 1/x ,x=3 ?
The answer to area 2x-1, 1/x ,x=3 is -ln(3)+6