What is the integral from 2 to 3 of 1/x ?

The integral from 2 to 3 of 1/x is ln(3)-ln(2)

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integral from 2 to 3 of 1/x

\int_{2}^{3} \frac{1}{x} d x

ln (3) - ln (2)

Solution steps

\int_{2}^{3} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= [ln ∣ x ∣]_{2}^{3}

Compute the boundaries:

ln (3) - ln (2)

= ln (3) - ln (2)

\int (6 x^{2} - 3 x + 3) d x

\frac{d}{d x} (cos (2 - 3 x))

\frac{d y}{d t} + e^{t} y = e^{t}

\frac{d ^{2} y}{d x ^{2}} - 4 \frac{d y}{d x} + 2 y = 0

x \to - \frac{7 π}{2} - lim (sec (x))

What is the integral from 2 to 3 of 1/x ?
The integral from 2 to 3 of 1/x is ln(3)-ln(2)