What is (\partial)/(\partial y)(1+x^2) ?

The answer to (\partial)/(\partial y)(1+x^2) is 0

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(\partial)/(\partial y)(1+x^2)

\frac{\partial}{\partial y} (1 + x^{2})

0

Solution steps

\frac{\partial}{\partial y} (1 + x^{2})

Treat

x

as a constant

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

arctan (\frac{x}{4})

\int \frac{( 4 - x ) ^{2}}{x} d x

\frac{e ^{x}}{e ^{x} + 3}

\int \frac{4 x}{x ^{2} + 1} d x

\int x^{2} \cdot 2^{x} d x

What is (\partial)/(\partial y)(1+x^2) ?
The answer to (\partial)/(\partial y)(1+x^2) is 0