What is the derivative of (4x+asqrt(1+x)/(x^2-1)) ?

The derivative of (4x+asqrt(1+x)/(x^2-1)) is (-8x^2-3axsqrt(x+1)-asqrt(x+1)-8)/(2(x^2-1)^2)

What is the first derivative of (4x+asqrt(1+x)/(x^2-1)) ?

The first derivative of (4x+asqrt(1+x)/(x^2-1)) is (-8x^2-3axsqrt(x+1)-asqrt(x+1)-8)/(2(x^2-1)^2)

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\frac{d}{d x} (\frac{4 x + a 1 + x}{x ^{2} - 1})

\frac{- 8 x ^{2} - 3 a x x + 1 - a x + 1 - 8}{2 ( x ^{2} - 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{4 x + a 1 + x}{x ^{2} - 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 4 x + a 1 + x ) ( x ^{2} - 1 ) - \frac{d}{d x} ( x ^{2} - 1 ) ( 4 x + a 1 + x )}{( x ^{2} - 1 ) ^{2}}

\frac{d}{d x} (4 x + a 1 + x) = 4 + \frac{a}{2 1 + x}

\frac{d}{d x} (x^{2} - 1) = 2 x

= \frac{( 4 + \frac{a}{2 1 + x} ) ( x ^{2} - 1 ) - 2 x ( 4 x + a 1 + x )}{( x ^{2} - 1 ) ^{2}}

Simplify

\frac{( 4 + \frac{a}{2 1 + x} ) ( x ^{2} - 1 ) - 2 x ( 4 x + a 1 + x )}{( x ^{2} - 1 ) ^{2}} : \frac{- 8 x ^{2} - 3 a x x + 1 - a x + 1 - 8}{2 ( x ^{2} - 1 ) ^{2}}

= \frac{- 8 x ^{2} - 3 a x x + 1 - a x + 1 - 8}{2 ( x ^{2} - 1 ) ^{2}}

d x + e^{2 x} d y = 0

\frac{A}{y ^{14}} + B e^{y}

x \to 2 - lim (- 3)

\frac{d}{d x} (x sin (tan (x)))

y = 3 x^{2} + 2 x^{2} + 1, (- 1, 0)

What is the derivative of (4x+asqrt(1+x)/(x^2-1)) ?
The derivative of (4x+asqrt(1+x)/(x^2-1)) is (-8x^2-3axsqrt(x+1)-asqrt(x+1)-8)/(2(x^2-1)^2)
What is the first derivative of (4x+asqrt(1+x)/(x^2-1)) ?
The first derivative of (4x+asqrt(1+x)/(x^2-1)) is (-8x^2-3axsqrt(x+1)-asqrt(x+1)-8)/(2(x^2-1)^2)