What is the derivative of sin(4x-5) ?

The derivative of sin(4x-5) is cos(4x-5)*4

What is the first derivative of sin(4x-5) ?

The first derivative of sin(4x-5) is cos(4x-5)*4

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\frac{d}{d x} (sin (4 x - 5))

cos (4 x - 5) \cdot 4

Solution steps

\frac{d}{d x} (sin (4 x - 5))

Apply the chain rule:

cos (4 x - 5) \frac{d}{d x} (4 x - 5)

= cos (4 x - 5) \frac{d}{d x} (4 x - 5)

\frac{d}{d x} (4 x - 5) = 4

= cos (4 x - 5) \cdot 4

(\frac{x}{sin ( y )} + 2) d x + \frac{( x ^{2} + 1 ) cos ( y )}{cos ( 2 y ) - 1} d y = 0

\int e^{6 x + e^{6 x}} d x

(- 4.4) (- 6.6)

\int (x + 4)^{3} d x

\frac{\partial}{\partial x} (2 x^{2} cos (x y))

What is the derivative of sin(4x-5) ?
The derivative of sin(4x-5) is cos(4x-5)*4
What is the first derivative of sin(4x-5) ?
The first derivative of sin(4x-5) is cos(4x-5)*4