What is the tangent of f(x)=(x^2+36)(2x+21),\at x=-4 ?

The tangent of f(x)=(x^2+36)(2x+21),\at x=-4 is y=676

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tangent of f(x)=(x^2+36)(2x+21),\at x=-4

tangent of

f (x) = (x^{2} + 36) (2 x + 21), at x = - 4

y = 676

Solution steps

Find the tangent point:

(- 4, 676)

Find the slope of

f (x) = (x^{2} + 36) (2 x + 21) : \frac{df ( x )}{d x} = 6 x^{2} + 42 x + 72

Compute the slope of

f (x) = (x^{2} + 36) (2 x + 21)

x = - 4 : m = 0

Find the line with slope m=

0

and passing through

(- 4, 676) : y = 676

y = 676

\int \frac{cosh ( x )}{sinh ( x )} d x

x \to 0 + lim (\frac{2}{3 x ^{\frac{1}{3}}})

f (x) = - 4 x^{2}

\frac{\partial}{\partial y} (x e^{2 x - 3 y})

x \to 0 lim (\frac{sin ( 4 x ) cos ( 3 x )}{7 x})

What is the tangent of f(x)=(x^2+36)(2x+21),\at x=-4 ?
The tangent of f(x)=(x^2+36)(2x+21),\at x=-4 is y=676