What is the integral of sin(2x)+cos(2x) ?

The integral of sin(2x)+cos(2x) is 1/2 sin(2x)-1/2 cos(2x)+C

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integral of sin(2x)+cos(2x)

\int sin (2 x) + cos (2 x) d x

\frac{1}{2} sin (2 x) - \frac{1}{2} cos (2 x) + C

Solution steps

\int sin (2 x) + cos (2 x) d x

Rewrite using trig identities

= \int - 1 + 2 cos^{2} (x) + sin (2 x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 1 d x + \int 2 cos^{2} (x) d x + \int sin (2 x) d x

\int 1 d x = x

\int 2 cos^{2} (x) d x = x + \frac{1}{2} sin (2 x)

\int sin (2 x) d x = - \frac{1}{2} cos (2 x)

= - x + x + \frac{1}{2} sin (2 x) - \frac{1}{2} cos (2 x)

Simplify

= \frac{1}{2} sin (2 x) - \frac{1}{2} cos (2 x)

Add a constant to the solution

= \frac{1}{2} sin (2 x) - \frac{1}{2} cos (2 x) + C

x = y - y^{2}, x = y^{2} - 3

y^{^{''}} - 4 y^{^{'}} - 45 y = 0

\int cos^{4} (3 t) d t

\int_{- π}^{π} x d x

\frac{d}{d x} (\frac{( x ^{2} )}{5 + 8 x})

What is the integral of sin(2x)+cos(2x) ?
The integral of sin(2x)+cos(2x) is 1/2 sin(2x)-1/2 cos(2x)+C