What is the sum from n=1 to infinity of 2^n*3^{-n} ?

The sum from n=1 to infinity of 2^n*3^{-n} is converges

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sum from n=1 to infinity of 2^n*3^{-n}

n = 1 \sum \infty 2^{n} \cdot 3^{- n}

converges

Solution steps

n = 1 \sum \infty 2^{n} \cdot 3^{- n}

Apply Series Ratio Test:

converges

= converges

y = 3 cos (x^{2} - 1)

\int 6 x + 5 d x

sin (y) = 5 x^{3} - 5

f (x) = x^{2} - x + 1, at x = - 1

h \to 0 lim (6 x + 3 h)

What is the sum from n=1 to infinity of 2^n*3^{-n} ?
The sum from n=1 to infinity of 2^n*3^{-n} is converges