What is the integral of 4sin^5(x)cos(x) ?

The integral of 4sin^5(x)cos(x) is 2/3 sin^6(x)+C

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integral of 4sin^5(x)cos(x)

\int 4 sin^{5} (x) cos (x) d x

\frac{2}{3} sin^{6} (x) + C

Solution steps

\int 4 sin^{5} (x) cos (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int sin^{5} (x) cos (x) d x

Apply u-substitution

: \int u^{5} d u

= 4 \cdot \int u^{5} d u

Apply the Power Rule

: \frac{u ^{6}}{6}

= 4 \cdot \frac{u ^{6}}{6}

Substitute back

u = sin (x)

= 4 \cdot \frac{sin ^{6} ( x )}{6}

Simplify

4 \cdot \frac{sin ^{6} ( x )}{6} : \frac{2}{3} sin^{6} (x)

= \frac{2}{3} sin^{6} (x)

Add a constant to the solution

= \frac{2}{3} sin^{6} (x) + C

\int_{1}^{4} - 4 t ln (t) d t

\frac{d}{d x} (- 235)

sin (x^{4})

y = 9^{5^{x^{2}}}

y = 2, y = 2 sin (x), [0, \frac{π}{2}]

What is the integral of 4sin^5(x)cos(x) ?
The integral of 4sin^5(x)cos(x) is 2/3 sin^6(x)+C