What is the tangent of f(x)= 3/x ,(5, 3/5) ?

The tangent of f(x)= 3/x ,(5, 3/5) is y=-3/25 x+6/5

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tangent of f(x)= 3/x ,(5, 3/5)

tangent of

f (x) = \frac{3}{x}, (5, \frac{3}{5})

y = - \frac{3}{25} x + \frac{6}{5}

Solution steps

Find the slope of

f (x) = \frac{3}{x} : \frac{df ( x )}{d x} = - \frac{3}{x ^{2}}

Compute the slope of

f (x) = \frac{3}{x}

(5, \frac{3}{5}) : m = - \frac{3}{25}

Find the line with slope m=

- \frac{3}{25}

and passing through

(5, \frac{3}{5}) : y = - \frac{3}{25} x + \frac{6}{5}

y = - \frac{3}{25} x + \frac{6}{5}

\int x^{4} e^{7 x} d x

\int \frac{x ^{2} - 3}{x ( x ^{2} - 1 )} d x

\int_{0}^{π} 4 sec^{2} (\frac{x}{4}) d x

\frac{\partial}{\partial x} (2 x^{3} cos (x y))

x \to 0 lim (\frac{1}{3 ^{x}})

What is the tangent of f(x)= 3/x ,(5, 3/5) ?
The tangent of f(x)= 3/x ,(5, 3/5) is y=-3/25 x+6/5