What is (\partial)/(\partial s)(-(sqrt(s^2+t^2))) ?

The answer to (\partial)/(\partial s)(-(sqrt(s^2+t^2))) is -s/(sqrt(s^2+t^2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial s)(-(sqrt(s^2+t^2)))

\frac{\partial}{\partial s} (- (s^{2} + t^{2}))

- \frac{s}{s ^{2} + t ^{2}}

Solution steps

\frac{\partial}{\partial s} (- (s^{2} + t^{2}))

Treat

t

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{\partial}{\partial s} (s^{2} + t^{2})

Apply the chain rule:

\frac{1}{2 s ^{2} + t ^{2}} \frac{\partial}{\partial s} (s^{2} + t^{2})

= \frac{1}{2 s ^{2} + t ^{2}} \frac{\partial}{\partial s} (s^{2} + t^{2})

\frac{\partial}{\partial s} (s^{2} + t^{2}) = 2 s

= - \frac{1}{2 s ^{2} + t ^{2}} \cdot 2 s

Simplify

- \frac{1}{2 s ^{2} + t ^{2}} \cdot 2 s : - \frac{s}{s ^{2} + t ^{2}}

= - \frac{s}{s ^{2} + t ^{2}}

\int_{1}^{e} ln (13 x) d x

\int e^{1 - 8 t} d t

\frac{\partial}{\partial u} (\frac{1}{4} (u - v))

f (x) = \frac{5 ^{4 x^{3}} + e ^{2 x^{3}}}{12}

\frac{d}{d x} ((3 x^{2} + 6 x) sin (x))

What is (\partial)/(\partial s)(-(sqrt(s^2+t^2))) ?
The answer to (\partial)/(\partial s)(-(sqrt(s^2+t^2))) is -s/(sqrt(s^2+t^2))