What is the derivative of 2/(sqrt(4x-3)) ?

The derivative of 2/(sqrt(4x-3)) is -4/((4x-3)^{3/2)}

What is the first derivative of 2/(sqrt(4x-3)) ?

The first derivative of 2/(sqrt(4x-3)) is -4/((4x-3)^{3/2)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (\frac{2}{4 x - 3})

- \frac{4}{( 4 x - 3 ) ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} (\frac{2}{4 x - 3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{1}{4 x - 3})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d x} ((4 x - 3)^{- \frac{1}{2}})

Apply the chain rule:

- \frac{1}{2 ( 4 x - 3 ) ^{\frac{3}{2}}} \frac{d}{d x} (4 x - 3)

= - \frac{1}{2 ( 4 x - 3 ) ^{\frac{3}{2}}} \frac{d}{d x} (4 x - 3)

\frac{d}{d x} (4 x - 3) = 4

= 2 (- \frac{1}{2 ( 4 x - 3 ) ^{\frac{3}{2}}} \cdot 4)

Simplify

2 (- \frac{1}{2 ( 4 x - 3 ) ^{\frac{3}{2}}} \cdot 4) : - \frac{4}{( 4 x - 3 ) ^{\frac{3}{2}}}

= - \frac{4}{( 4 x - 3 ) ^{\frac{3}{2}}}

\int \frac{t ^{3}}{a ^{4} + t ^{4}} d t

\frac{d}{d x} (arctan (7 x))

y^{^{'}} = x - y + 1

f (x) = \frac{1300 + 8 x - 0.0004 x ^{2}}{x}

\frac{s + 1}{s ^{2} + 1}

What is the derivative of 2/(sqrt(4x-3)) ?
The derivative of 2/(sqrt(4x-3)) is -4/((4x-3)^{3/2)}
What is the first derivative of 2/(sqrt(4x-3)) ?
The first derivative of 2/(sqrt(4x-3)) is -4/((4x-3)^{3/2)}