What is the integral of 2ln(t) ?

The integral of 2ln(t) is 2(tln(t)-t)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 2ln(t)

\int 2 ln (t) d t

2 (t ln (t) - t) + C

Solution steps

\int 2 ln (t) d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int ln (t) d t

Apply Integration By Parts

: t ln (t) - \int 1 d t

= 2 (t ln (t) - \int 1 d t)

\int 1 d t = t

= 2 (t ln (t) - t)

Add a constant to the solution

= 2 (t ln (t) - t) + C

y^{^{'}} = 1 - 7 x^{2}

\int \frac{x - 2}{x + 3} d x

\int cos (\frac{nπ x}{L}) d x

\frac{d}{d x} (2 (x)^{4})

\frac{d}{d x} (\frac{6 x ^{2} + 4}{3 y ^{2} - 4})