What is the derivative of (10/(x^2+1)) ?

The derivative of (10/(x^2+1)) is -(20x)/((x^2+1)^2)

What is the first derivative of (10/(x^2+1)) ?

The first derivative of (10/(x^2+1)) is -(20x)/((x^2+1)^2)

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\frac{d}{d x} (\frac{10}{x ^{2} + 1})

- \frac{20 x}{( x ^{2} + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{10}{x ^{2} + 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 10 \frac{d}{d x} (\frac{1}{x ^{2} + 1})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 10 \frac{d}{d x} ((x^{2} + 1)^{- 1})

Apply the chain rule:

- \frac{1}{( x ^{2} + 1 ) ^{2}} \frac{d}{d x} (x^{2} + 1)

= - \frac{1}{( x ^{2} + 1 ) ^{2}} \frac{d}{d x} (x^{2} + 1)

\frac{d}{d x} (x^{2} + 1) = 2 x

= 10 (- \frac{1}{( x ^{2} + 1 ) ^{2}} \cdot 2 x)

Simplify

10 (- \frac{1}{( x ^{2} + 1 ) ^{2}} \cdot 2 x) : - \frac{20 x}{( x ^{2} + 1 ) ^{2}}

= - \frac{20 x}{( x ^{2} + 1 ) ^{2}}

x \to - 4 lim (\frac{1}{2} x - 1)

\frac{7 e ^{x} x ^{\frac{5}{2}}}{2} + e^{x} x^{\frac{7}{2}}

\int 0.4 \cdot e^{- 2000 x} d x

\frac{\partial}{\partial x} (\frac{x ^{2} + 2}{x ^{2} - 2})

x \to - 3 lim ((5 - x)^{\frac{4}{3}})

What is the derivative of (10/(x^2+1)) ?
The derivative of (10/(x^2+1)) is -(20x)/((x^2+1)^2)
What is the first derivative of (10/(x^2+1)) ?
The first derivative of (10/(x^2+1)) is -(20x)/((x^2+1)^2)