What is the derivative of f(x)=(x^2-1)/(x-1) ?

The derivative of f(x)=(x^2-1)/(x-1) is 1

What is the first derivative of f(x)=(x^2-1)/(x-1) ?

The first derivative of f(x)=(x^2-1)/(x-1) is 1

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derivative of

f (x) = \frac{x ^{2} - 1}{x - 1}

1

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 1}{x - 1})

Simplify

\frac{x ^{2} - 1}{x - 1} : x + 1

= \frac{d}{d x} (x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (1)

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= 1 + 0

Simplify

= 1

x \to - 5 lim (\frac{4 ( 2 x + 3 ) ^{2} - 196}{x + 5})

\frac{d}{d x} (ln (\frac{( 2 x + 1 ) ^{2}}{( x - 1 )}))

\frac{( 2 s + 1 )}{s ^{2} + 10 + 25}

tan (3 x), 2 sin (3 x), - \frac{π}{9}, \frac{π}{9}

What is the derivative of f(x)=(x^2-1)/(x-1) ?
The derivative of f(x)=(x^2-1)/(x-1) is 1
What is the first derivative of f(x)=(x^2-1)/(x-1) ?
The first derivative of f(x)=(x^2-1)/(x-1) is 1