What is the derivative of y=3x^{2/3}-2x ?

The derivative of y=3x^{2/3}-2x is 2/(x^{1/3)}-2

What is the first derivative of y=3x^{2/3}-2x ?

The first derivative of y=3x^{2/3}-2x is 2/(x^{1/3)}-2

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derivative of

y = 3 x^{\frac{2}{3}} - 2 x

\frac{2}{x ^{\frac{1}{3}}} - 2

Solution steps

\frac{d}{d x} (3 x^{\frac{2}{3}} - 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{\frac{2}{3}}) - \frac{d}{d x} (2 x)

\frac{d}{d x} (3 x^{\frac{2}{3}}) = \frac{2}{x ^{\frac{1}{3}}}

\frac{d}{d x} (2 x) = 2

= \frac{2}{x ^{\frac{1}{3}}} - 2

\int_{- 3}^{0} (x^{2} - 4 x + 7) d x

\int (x + 3) 2 - x d x

x \to 4 - lim (5 (x) - 7)

arccos (1 - x^{2})

y = 2 x^{2} + 5 x

What is the derivative of y=3x^{2/3}-2x ?
The derivative of y=3x^{2/3}-2x is 2/(x^{1/3)}-2
What is the first derivative of y=3x^{2/3}-2x ?
The first derivative of y=3x^{2/3}-2x is 2/(x^{1/3)}-2