What is (\partial}{\partial y}(\frac{3x)/y) ?

The answer to (\partial}{\partial y}(\frac{3x)/y) is -(3x)/(y^2)

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(\partial}{\partial y}(\frac{3x)/y)

\frac{\partial}{\partial y} (\frac{3 x}{y})

- \frac{3 x}{y ^{2}}

Solution steps

\frac{\partial}{\partial y} (\frac{3 x}{y})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 x \frac{\partial}{\partial y} (\frac{1}{y})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 3 x \frac{\partial}{\partial y} (y^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 x (- 1 \cdot y^{- 1 - 1})

Simplify

3 x (- 1 \cdot y^{- 1 - 1}) : - \frac{3 x}{y ^{2}}

= - \frac{3 x}{y ^{2}}

\frac{d}{d x} (2 - cos (x))

\frac{\partial}{\partial x} (x y + 6 x)

\int \frac{cos ^{5} ( x )}{sin ( x )} d x

n = 1 \sum \infty \frac{1}{n n}

\int_{\frac{3}{2}}^{\frac{5}{2}} e^{- s t} d t

What is (\partial}{\partial y}(\frac{3x)/y) ?
The answer to (\partial}{\partial y}(\frac{3x)/y) is -(3x)/(y^2)