What is the ((x^2)/((x-2)^2))^' ?

The ((x^2)/((x-2)^2))^' is -(4x)/((x-2)^3)

What is the first ((x^2)/((x-2)^2))^' ?

The first ((x^2)/((x-2)^2))^' is -(4x)/((x-2)^3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\frac{x ^{2}}{( x - 2 ) ^{2}})^{^{'}}

- \frac{4 x}{( x - 2 ) ^{3}}

Solution steps

(\frac{x ^{2}}{( x - 2 ) ^{2}})^{'}

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{( x ^{2} ) ^{^{'}} ( x - 2 ) ^{2} - ( ( x - 2 ) ^{2} ) ^{^{'}} x ^{2}}{( ( x - 2 ) ^{2} ) ^{2}}

(x^{2})^{'} = 2 x

((x - 2)^{2})^{'} = 2 (x - 2)

= \frac{2 x ( x - 2 ) ^{2} - 2 ( x - 2 ) x ^{2}}{( ( x - 2 ) ^{2} ) ^{2}}

Simplify

\frac{2 x ( x - 2 ) ^{2} - 2 ( x - 2 ) x ^{2}}{( ( x - 2 ) ^{2} ) ^{2}} : - \frac{4 x}{( x - 2 ) ^{3}}

= - \frac{4 x}{( x - 2 ) ^{3}}

\int (sin (2 x)) d x

\frac{d y}{d x} = x^{2} - \frac{1}{2} y

\frac{\partial}{\partial x} (x^{3} + 2)

\frac{d}{d x} (x^{4} e^{- 3 x})

x^{2} 8 x - 7

What is the ((x^2)/((x-2)^2))^' ?
The ((x^2)/((x-2)^2))^' is -(4x)/((x-2)^3)
What is the first ((x^2)/((x-2)^2))^' ?
The first ((x^2)/((x-2)^2))^' is -(4x)/((x-2)^3)