What is the derivative of 4x^3-6x^2+8x-4 ?

The derivative of 4x^3-6x^2+8x-4 is 12x^2-12x+8

What is the first derivative of 4x^3-6x^2+8x-4 ?

The first derivative of 4x^3-6x^2+8x-4 is 12x^2-12x+8

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derivative of

4 x^{3} - 6 x^{2} + 8 x - 4

12 x^{2} - 12 x + 8

Solution steps

\frac{d}{d x} (4 x^{3} - 6 x^{2} + 8 x - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{3}) - \frac{d}{d x} (6 x^{2}) + \frac{d}{d x} (8 x) - \frac{d}{d x} (4)

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

\frac{d}{d x} (6 x^{2}) = 12 x

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (4) = 0

= 12 x^{2} - 12 x + 8 - 0

Simplify

= 12 x^{2} - 12 x + 8

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What is the derivative of 4x^3-6x^2+8x-4 ?
The derivative of 4x^3-6x^2+8x-4 is 12x^2-12x+8
What is the first derivative of 4x^3-6x^2+8x-4 ?
The first derivative of 4x^3-6x^2+8x-4 is 12x^2-12x+8