What is the derivative of x^2+xy+y^2 ?

The derivative of x^2+xy+y^2 is 2x+y+x(dy)/(dx)+2y(dy)/(dx)

What is the first derivative of x^2+xy+y^2 ?

The first derivative of x^2+xy+y^2 is 2x+y+x(dy)/(dx)+2y(dy)/(dx)

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\frac{d}{d x} (x^{2} + x y + y^{2})

2 x + y + x \frac{d y}{d x} + 2 y \frac{d y}{d x}

Solution steps

\frac{d}{d x} (x^{2} + x y + y^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (x y) + \frac{d}{d x} (y^{2})

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (x y) = y + x \frac{d y}{d x}

\frac{d}{d x} (y^{2}) = 2 y \frac{d y}{d x}

= 2 x + y + x \frac{d y}{d x} + 2 y \frac{d y}{d x}

\int e^{t^{2}} \cdot t^{3} d t

\frac{d}{d x} (- 7 x - 10)

\int 2^{2} d x

tan^{3} (x)

\frac{5 t - 2}{3 t + 1}

What is the derivative of x^2+xy+y^2 ?
The derivative of x^2+xy+y^2 is 2x+y+x(dy)/(dx)+2y(dy)/(dx)
What is the first derivative of x^2+xy+y^2 ?
The first derivative of x^2+xy+y^2 is 2x+y+x(dy)/(dx)+2y(dy)/(dx)