What is the derivative of 4/(x^4-4\sqrt[5]{x}) ?

The derivative of 4/(x^4-4\sqrt[5]{x}) is (-80x^{4/5}-4x^5)/(5x^{29/5)}

What is the first derivative of 4/(x^4-4\sqrt[5]{x}) ?

The first derivative of 4/(x^4-4\sqrt[5]{x}) is (-80x^{4/5}-4x^5)/(5x^{29/5)}

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\frac{d}{d x} (\frac{4}{x ^{4}} - 4 5 x)

\frac{- 80 x ^{\frac{4}{5}} - 4 x ^{5}}{5 x ^{\frac{29}{5}}}

Solution steps

\frac{d}{d x} (\frac{4}{x ^{4}} - 4 5 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{4}{x ^{4}}) - \frac{d}{d x} (4 5 x)

\frac{d}{d x} (\frac{4}{x ^{4}}) = - \frac{16}{x ^{5}}

\frac{d}{d x} (4 5 x) = \frac{4}{5 x ^{\frac{4}{5}}}

= - \frac{16}{x ^{5}} - \frac{4}{5 x ^{\frac{4}{5}}}

Simplify

- \frac{16}{x ^{5}} - \frac{4}{5 x ^{\frac{4}{5}}} : \frac{- 80 x ^{\frac{4}{5}} - 4 x ^{5}}{5 x ^{\frac{29}{5}}}

= \frac{- 80 x ^{\frac{4}{5}} - 4 x ^{5}}{5 x ^{\frac{29}{5}}}

\int x^{2} x^{3} + 27 d x

\frac{d}{d y} (e^{- 2 y})

\frac{d}{d x} (x^{5} - x^{3} + 3)

f (x) = 4 x - 11 x

x \to \infty lim (x^{2} + 4)

What is the derivative of 4/(x^4-4\sqrt[5]{x}) ?
The derivative of 4/(x^4-4\sqrt[5]{x}) is (-80x^{4/5}-4x^5)/(5x^{29/5)}
What is the first derivative of 4/(x^4-4\sqrt[5]{x}) ?
The first derivative of 4/(x^4-4\sqrt[5]{x}) is (-80x^{4/5}-4x^5)/(5x^{29/5)}