What is the solution for (dy)/(dx)=((5y^3-2xy))/(x^2) ?

The solution for (dy)/(dx)=((5y^3-2xy))/(x^2) is y=sqrt(x/(2+c_{1)x^5)},y=-sqrt(x/(2+c_{1)x^5)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=((5y^3-2xy))/(x^2)

\frac{d y}{d x} = \frac{( 5 y ^{3} - 2 x y )}{x ^{2}}

y = \frac{x}{2 + c _{1} x ^{5}}, y = - \frac{x}{2 + c _{1} x ^{5}}

Solution steps

\frac{d y}{d x} = \frac{( 5 y ^{3} - 2 x y )}{x ^{2}}

Solve Bernoulli ODE:

y = \frac{x}{2 + c _{1} x ^{5}}, y = - \frac{x}{2 + c _{1} x ^{5}}

y = \frac{x}{2 + c _{1} x ^{5}}, y = - \frac{x}{2 + c _{1} x ^{5}}

(1 + cos^{2} (x))^{4}

y = x^{3} - 16 x^{2} + 45 x + 6

\int 4 sin (x) + 4 d x

\frac{d y}{d x} = \frac{1}{4} y

x \to - 5 - lim (\frac{6}{x ^{2} - 25})

What is the solution for (dy)/(dx)=((5y^3-2xy))/(x^2) ?
The solution for (dy)/(dx)=((5y^3-2xy))/(x^2) is y=sqrt(x/(2+c_{1)x^5)},y=-sqrt(x/(2+c_{1)x^5)}