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Popular >

y(x+1)+y^'=0

Solution

y (x + 1) + y^{^{'}} = 0

Solution

y = e^{- \frac{x ^{2}}{2} - x + c_{1}}

Solution steps

y (x + 1) + y^{'} (x) = 0

Solve separable ODE:

y = e^{- \frac{x ^{2}}{2} - x + c_{1}}

y = e^{- \frac{x ^{2}}{2} - x + c_{1}}

Popular Examples

derivative of 2\sqrt[4]{9-x^2}derivative of

integral of (cos(θ))/(sqrt(2+sin^2(θ)))

\int \frac{cos ( θ )}{2 + sin ^{2} ( θ )} d θ

derivative of f(-7)= 1/(x+3)derivative of

f (- 7) = \frac{1}{x + 3}

derivative of y= 2/(3x^2)derivative of

y = \frac{2}{3 x ^{2}}

limit as x approaches 0 of (4x^2)/x

x \to 0 lim (\frac{4 x ^{2}}{x})

Frequently Asked Questions (FAQ)

What is the solution for y(x+1)+y^'=0 ?
The solution for y(x+1)+y^'=0 is y=e^{-(x^2)/2-x+c_{1}}