What is derivative of f(x)=6+2/x+3/(x^2),x=x ?

The answer to derivative of f(x)=6+2/x+3/(x^2),x=x is -2/(x^2)-6/(x^3)

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derivative of f(x)=6+2/x+3/(x^2),x=x

derivative of

f (x) = 6 + \frac{2}{x} + \frac{3}{x ^{2}}, x = x

- \frac{2}{x ^{2}} - \frac{6}{x ^{3}}

Solution steps

\frac{d}{d x} (6 + \frac{2}{x} + \frac{3}{x ^{2}}) = - \frac{2}{x ^{2}} - \frac{6}{x ^{3}}

Find the value of

- \frac{2}{x ^{2}} - \frac{6}{x ^{3}}

for

x = x : - \frac{2}{x ^{2}} - \frac{6}{x ^{3}}

- \frac{2}{x ^{2}} - \frac{6}{x ^{3}}

f (x) = 2 x^{2} - 3 x + 3

\int \frac{x ^{2} + 2 x + 3}{x ^{3} + 3 x ^{2} + 9 x} d x

y = x^{2} - 2 x + 3, [- 2, 2]

\int_{0}^{1} \frac{7}{1 + t ^{2}} d t

\frac{d}{d x} (6 + 2 ln (x))

What is derivative of f(x)=6+2/x+3/(x^2),x=x ?
The answer to derivative of f(x)=6+2/x+3/(x^2),x=x is -2/(x^2)-6/(x^3)