What is the derivative of 5^x-1 ?

The derivative of 5^x-1 is ln(5)*5^x

What is the first derivative of 5^x-1 ?

The first derivative of 5^x-1 is ln(5)*5^x

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\frac{d}{d x} (5^{x} - 1)

ln (5) \cdot 5^{x}

Solution steps

\frac{d}{d x} (5^{x} - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (5^{x}) - \frac{d}{d x} (1)

\frac{d}{d x} (5^{x}) = 5^{x} ln (5)

\frac{d}{d x} (1) = 0

= 5^{x} ln (5) - 0

Simplify

= ln (5) \cdot 5^{x}

\frac{sin ( x ) + cos ( x )}{e ^{x}}

\int (3 x + 1) (3 x^{2} + 2 x)^{\frac{1}{3}} d x

\frac{d}{d x} (\frac{1}{x ^{2} - 2 x + 2})

x \to 0 lim (\frac{2 x + 1}{∣ x ∣})

y^{^{''}} - 4 y^{^{'}} - 4 y = 0

What is the derivative of 5^x-1 ?
The derivative of 5^x-1 is ln(5)*5^x
What is the first derivative of 5^x-1 ?
The first derivative of 5^x-1 is ln(5)*5^x