What is the solution for (df)/(dx)f(x)=cos(2x) ?

The solution for (df)/(dx)f(x)=cos(2x) is f(x)=sqrt(sin(2x)+c_{1)},f(x)=-sqrt(sin(2x)+c_{1)}

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(df)/(dx)f(x)=cos(2x)

\frac{df}{d x} f (x) = cos (2 x)

f (x) = sin (2 x) + c_{1}, f (x) = - sin (2 x) + c_{1}

Solution steps

\frac{df}{d x} f = cos (2 x)

Solve separable ODE:

f (x) = sin (2 x) + c_{1}, f (x) = - sin (2 x) + c_{1}

f (x) = sin (2 x) + c_{1}, f (x) = - sin (2 x) + c_{1}

(cos (7 x)) y^{^{'}} - 7 (tan (7 x)) y = 9 sec (7 x)

1 - x^{2}, 29 - 11 x

n = 0 \sum \infty \frac{5 ^{n}}{8 ^{n}}

\frac{2 x ^{3}}{5}

\int_{1}^{2} \frac{3}{x ^{4}} d x

What is the solution for (df)/(dx)f(x)=cos(2x) ?
The solution for (df)/(dx)f(x)=cos(2x) is f(x)=sqrt(sin(2x)+c_{1)},f(x)=-sqrt(sin(2x)+c_{1)}