What is the integral of t^2cos(t) ?

The integral of t^2cos(t) is t^2sin(t)-2(-tcos(t)+sin(t))+C

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integral of t^2cos(t)

\int t^{2} cos (t) d t

t^{2} sin (t) - 2 (- t cos (t) + sin (t)) + C

Solution steps

\int t^{2} cos (t) d t

Apply Integration By Parts

: t^{2} sin (t) - \int 2 t sin (t) d t

= t^{2} sin (t) - \int 2 t sin (t) d t

\int 2 t sin (t) d t = 2 (- t cos (t) + sin (t))

= t^{2} sin (t) - 2 (- t cos (t) + sin (t))

Add a constant to the solution

= t^{2} sin (t) - 2 (- t cos (t) + sin (t)) + C

\int \frac{- 3}{x ^{2} + 1} d x

x \to 1 lim (7 - 2 x)

\int - \frac{1}{y} d y

(x - 9) (x - 3)^{2}

y = \frac{e ^{x} + e ^{- x}}{e ^{x} - e ^{- x}}

What is the integral of t^2cos(t) ?
The integral of t^2cos(t) is t^2sin(t)-2(-tcos(t)+sin(t))+C