What is the (sin(x)-xcos(x))^' ?

The (sin(x)-xcos(x))^' is xsin(x)

What is the first (sin(x)-xcos(x))^' ?

The first (sin(x)-xcos(x))^' is xsin(x)

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(sin (x) - x cos (x))^{^{'}}

x sin (x)

Solution steps

(sin (x) - x cos (x))^{'}

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= (sin (x))^{^{'}} - (x cos (x))^{^{'}}

(sin (x))^{'} = cos (x)

(x cos (x))^{'} = cos (x) - x sin (x)

= cos (x) - (cos (x) - x sin (x))

Simplify

= x sin (x)

y^{^{'}} = 20 x y

\int 3 x sin (\frac{1}{6} x) d x

f (x) = - \frac{1}{x}

n = 1 \sum \infty 6 sin (\frac{1}{n})

\frac{12 ( s + 1 )}{s ( s ^{2} + 9 )}