What is the derivative of f(x)=((x+8)/(x-8))^5 ?

The derivative of f(x)=((x+8)/(x-8))^5 is -(80(x+8)^4)/((x-8)^6)

What is the first derivative of f(x)=((x+8)/(x-8))^5 ?

The first derivative of f(x)=((x+8)/(x-8))^5 is -(80(x+8)^4)/((x-8)^6)

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derivative of

f (x) = (\frac{x + 8}{x - 8})^{5}

- \frac{80 ( x + 8 ) ^{4}}{( x - 8 ) ^{6}}

Solution steps

\frac{d}{d x} ((\frac{x + 8}{x - 8})^{5})

Apply the chain rule:

5 (\frac{x + 8}{x - 8})^{4} \frac{d}{d x} (\frac{x + 8}{x - 8})

= 5 (\frac{x + 8}{x - 8})^{4} \frac{d}{d x} (\frac{x + 8}{x - 8})

\frac{d}{d x} (\frac{x + 8}{x - 8}) = - \frac{16}{( x - 8 ) ^{2}}

= 5 (\frac{x + 8}{x - 8})^{4} (- \frac{16}{( x - 8 ) ^{2}})

Simplify

5 (\frac{x + 8}{x - 8})^{4} (- \frac{16}{( x - 8 ) ^{2}}) : - \frac{80 ( x + 8 ) ^{4}}{( x - 8 ) ^{6}}

= - \frac{80 ( x + 8 ) ^{4}}{( x - 8 ) ^{6}}

\int \frac{- e ^{\frac{1}{x}}}{x ^{2}} d x

\int (x - y) d x

\frac{\partial}{\partial x} (e^{4 e^{x}})

x + \frac{2}{x}

\frac{d}{d x} (3^{s i n (x)} + \frac{e ^{- x}}{2})

What is the derivative of f(x)=((x+8)/(x-8))^5 ?
The derivative of f(x)=((x+8)/(x-8))^5 is -(80(x+8)^4)/((x-8)^6)
What is the first derivative of f(x)=((x+8)/(x-8))^5 ?
The first derivative of f(x)=((x+8)/(x-8))^5 is -(80(x+8)^4)/((x-8)^6)