What is the integral from-1 to x^3 of t^5 ?

The integral from-1 to x^3 of t^5 is (x^{18}-1)/6

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integral from-1 to x^3 of t^5

\int_{- 1}^{x^{3}} t^{5} d t

\frac{x ^{18} - 1}{6}

Solution steps

\int_{- 1}^{x^{3}} t^{5} d t

Apply the Power Rule

: [\frac{t ^{6}}{6}]_{- 1}^{x^{3}}

= [\frac{t ^{6}}{6}]_{- 1}^{x^{3}}

Compute the boundaries:

\frac{x ^{18}}{6} - \frac{1}{6}

= \frac{x ^{18}}{6} - \frac{1}{6}

Simplify

= \frac{x ^{18} - 1}{6}

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What is the integral from-1 to x^3 of t^5 ?
The integral from-1 to x^3 of t^5 is (x^{18}-1)/6