What is the solution for (dy)/(dx)=xe^{x^2-y} ?

The solution for (dy)/(dx)=xe^{x^2-y} is y=ln(1/2 e^{x^2}+c_{1})

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(dy)/(dx)=xe^{x^2-y}

\frac{d y}{d x} = x e^{x^{2} - y}

y = ln (\frac{1}{2} e^{x^{2}} + c_{1})

Solution steps

\frac{d y}{d x} = x e^{x^{2} - y}

Solve separable ODE:

y = ln (\frac{1}{2} e^{x^{2}} + c_{1})

y = ln (\frac{1}{2} e^{x^{2}} + c_{1})

\int x^{3} \cdot e^{x^{2}} d x

\int \frac{8}{x} + 8 x d x

\frac{\partial}{\partial y} (\frac{x}{( x ^{3} + y ^{2} )})

y = - \frac{e ^{- x}}{2} cos (2 x)

f (x) = x^{3} - 4 x^{2} - 1

What is the solution for (dy)/(dx)=xe^{x^2-y} ?
The solution for (dy)/(dx)=xe^{x^2-y} is y=ln(1/2 e^{x^2}+c_{1})