What is the derivative of y=6e^x+2/(\sqrt[3]{x)} ?

The derivative of y=6e^x+2/(\sqrt[3]{x)} is 6e^x-2/(3x^{4/3)}

What is the first derivative of y=6e^x+2/(\sqrt[3]{x)} ?

The first derivative of y=6e^x+2/(\sqrt[3]{x)} is 6e^x-2/(3x^{4/3)}

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derivative of

6 e^{x} - \frac{2}{3 x ^{\frac{4}{3}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (6 e^{x}) = 6 e^{x}

= 6 e^{x} - \frac{2}{3 x ^{\frac{4}{3}}}

\int \frac{3}{2 x ^{2} - 4 x + 10} d x

\frac{d}{d x} (x^{3} 5 - x^{2})

\frac{d y}{d x}, x^{2} + y^{2} = 25

x \to 2 lim ([g (x)]^{3})

f (x) = \frac{e ^{2 x}}{sin ( 3 x )}

What is the derivative of y=6e^x+2/(\sqrt[3]{x)} ?
The derivative of y=6e^x+2/(\sqrt[3]{x)} is 6e^x-2/(3x^{4/3)}
What is the first derivative of y=6e^x+2/(\sqrt[3]{x)} ?
The first derivative of y=6e^x+2/(\sqrt[3]{x)} is 6e^x-2/(3x^{4/3)}