What is the tangent of 2x^2-3x,\at x=4 ?

The tangent of 2x^2-3x,\at x=4 is y=13x-32

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tangent of 2x^2-3x,\at x=4

tangent of

2 x^{2} - 3 x, at x = 4

y = 13 x - 32

Solution steps

Find the tangent point:

(4, 20)

Find the slope of

y = 2 x^{2} - 3 x : \frac{d y}{d x} = 4 x - 3

Compute the slope of

y = 2 x^{2} - 3 x

x = 4 : m = 13

Find the line with slope m=

13

and passing through

(4, 20) : y = 13 x - 32

y = 13 x - 32

\frac{d x}{d t} = 4 x t^{5}

y = x^{2} - 1, y = 5 - x

f (x) = 5 x + \frac{4}{x}

\frac{d}{d x} (\frac{5}{1 - 4 x ^{2}})

\frac{x + 2}{x ^{3} + x - 6}

What is the tangent of 2x^2-3x,\at x=4 ?
The tangent of 2x^2-3x,\at x=4 is y=13x-32