What is area e^{3x},e^{7x},x=1 ?

The answer to area e^{3x},e^{7x},x=1 is (3e^7-7e^3+4)/(21)

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area e^{3x},e^{7x},x=1

area

e^{3 x}, e^{7 x}, x = 1

\frac{3 e ^{7} - 7 e ^{3} + 4}{21}

Solution steps

Apply the area formula:

\int_{0}^{1} e^{3 x} - e^{7 x} d x

Solve

\int_{0}^{1} e^{3 x} - e^{7 x} d x : \frac{3 e ^{7} - 7 e ^{3} + 4}{21}

The area is:

= \frac{3 e ^{7} - 7 e ^{3} + 4}{21}

n = 1 \sum \infty (1.06)^{n}

x \to - 2 lim (\frac{2 x ^{2}}{2 x + 2})

x - 5 + \frac{1}{x}

x^{9 x}

y^{^{'}} + 8 (tan (8 x)) \cdot y = - 9 cos (8 x)

What is area e^{3x},e^{7x},x=1 ?
The answer to area e^{3x},e^{7x},x=1 is (3e^7-7e^3+4)/(21)