What is the derivative of y=ln(8x) ?

The derivative of y=ln(8x) is 1/x

What is the first derivative of y=ln(8x) ?

The first derivative of y=ln(8x) is 1/x

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derivative of

y = ln (8 x)

\frac{1}{x}

Solution steps

\frac{d}{d x} (ln (8 x))

Apply the chain rule:

\frac{1}{8 x} \frac{d}{d x} (8 x)

= \frac{1}{8 x} \frac{d}{d x} (8 x)

\frac{d}{d x} (8 x) = 8

= \frac{1}{8 x} \cdot 8

Simplify

\frac{1}{8 x} \cdot 8 : \frac{1}{x}

= \frac{1}{x}

y^{^{''}} - 7 y^{^{'}} = 5 t

x \to 0 lim (\frac{x}{sin ( 4 x )})

\int_{2}^{4} \frac{1}{x ^{2} + 1} d x

\frac{\partial}{\partial x} (y^{7 x})

y^{^{'}} = \frac{1}{2} y

What is the derivative of y=ln(8x) ?
The derivative of y=ln(8x) is 1/x
What is the first derivative of y=ln(8x) ?
The first derivative of y=ln(8x) is 1/x