What is laplacetransform sin(t-pi) ?

The answer to laplacetransform sin(t-pi) is -1/(s^2+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

laplacetransform sin(t-pi)

laplace transform

sin (t - π)

- \frac{1}{s ^{2} + 1}

Solution steps

L {sin (t - π)}

Use Laplace Transform table:

L {sin (a t + b)} = \frac{s \cdot sin ( b ) + a \cdot cos ( b )}{s ^{2} + a ^{2}}

L {sin (t - π)} = \frac{s sin ( - π ) + 1 \cdot cos ( - π )}{s ^{2} + 1 ^{2}}

= \frac{s sin ( - π ) + 1 \cdot cos ( - π )}{s ^{2} + 1 ^{2}}

= - \frac{1}{s ^{2} + 1}

\int \frac{3 x}{x ^{2} - x - 2} d x

(x - 1) d y + (y - x^{2} + 2 x^{- 3}) d x = 0

x = y^{\frac{1}{2}}, x = 2 [0, 2]

f (x) = x^{2}, at x = 0.2

f (x) = \frac{7}{x ^{2}}

What is laplacetransform sin(t-pi) ?
The answer to laplacetransform sin(t-pi) is -1/(s^2+1)