What is the derivative of f(x)=e^x+e^{-x} ?

The derivative of f(x)=e^x+e^{-x} is e^x-e^{-x}

What is the first derivative of f(x)=e^x+e^{-x} ?

The first derivative of f(x)=e^x+e^{-x} is e^x-e^{-x}

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derivative of

f (x) = e^{x} + e^{- x}

e^{x} - e^{- x}

Solution steps

\frac{d}{d x} (e^{x} + e^{- x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{x}) + \frac{d}{d x} (e^{- x})

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (e^{- x}) = - e^{- x}

= e^{x} - e^{- x}

t \to 0 lim (\frac{1 - cos ( t )}{t})

\frac{d}{d x} (4 cos (\frac{x}{2}))

y^{^{''}} - 3 y = 0

x \to 0 + lim (arctan (\frac{2}{x}))

y^{^{''}} + 2 y^{^{'}} + 20 y = 0, y (0) = 1, y^{^{'}} (0) = 0

What is the derivative of f(x)=e^x+e^{-x} ?
The derivative of f(x)=e^x+e^{-x} is e^x-e^{-x}
What is the first derivative of f(x)=e^x+e^{-x} ?
The first derivative of f(x)=e^x+e^{-x} is e^x-e^{-x}