What is the derivative of 2sin^2(2x) ?

The derivative of 2sin^2(2x) is 4sin(4x)

What is the first derivative of 2sin^2(2x) ?

The first derivative of 2sin^2(2x) is 4sin(4x)

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\frac{d}{d x} (2 sin^{2} (2 x))

4 sin (4 x)

Solution steps

\frac{d}{d x} (2 sin^{2} (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (sin^{2} (2 x))

Apply the chain rule:

2 sin (2 x) \frac{d}{d x} (sin (2 x))

= 2 sin (2 x) \frac{d}{d x} (sin (2 x))

\frac{d}{d x} (sin (2 x)) = cos (2 x) \cdot 2

= 2 \cdot 2 sin (2 x) cos (2 x) \cdot 2

Simplify

2 \cdot 2 sin (2 x) cos (2 x) \cdot 2 : 4 sin (4 x)

= 4 sin (4 x)

f (x) = \frac{3}{x - 6}

x \to - 2 - lim (\frac{x ^{2}}{x + 2})

n \to \infty lim (n^{2})

\frac{d}{d x} (e^{- x} \cdot ln (x))

y = 2 x^{3} - 3 x, (1, - 1)

What is the derivative of 2sin^2(2x) ?
The derivative of 2sin^2(2x) is 4sin(4x)
What is the first derivative of 2sin^2(2x) ?
The first derivative of 2sin^2(2x) is 4sin(4x)