What is the tangent of y=sqrt(2x),(32,8) ?

The tangent of y=sqrt(2x),(32,8) is y= 1/8 x+4

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tangent of y=sqrt(2x),(32,8)

tangent of

y = 2 x, (32, 8)

y = \frac{1}{8} x + 4

Solution steps

Find the slope of

y = 2 x : \frac{d y}{d x} = \frac{1}{2 x}

Compute the slope of

y = 2 x

(32, 8) : m = \frac{1}{8}

Find the line with slope m=

\frac{1}{8}

and passing through

(32, 8) : y = \frac{1}{8} x + 4

y = \frac{1}{8} x + 4

\int cos (14 x) cos (5 x) d x

\int \frac{tan ( x ) + 1}{cos ^{2} ( x )} d x

\frac{\partial}{\partial y} (y^{5} cos (2 x))

\int \frac{3 x ^{2}}{x ^{3} + 8} d x

What is the tangent of y=sqrt(2x),(32,8) ?
The tangent of y=sqrt(2x),(32,8) is y= 1/8 x+4